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Question
Factorise completely: 5b2 + 45b + 90
Sum
Solution
5b2 + 45b + 90 = 5[b2 + 9b + 18]
= 5[b2 + 6b + 3b + 18]
= 5[b(b + 6) + 3(b + 6)]
= 5[(b + 6) (b + 3)]
= 5 (b + 6)(b + 3)
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Factorising Completely
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