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Question
Factorise completely: 2a2 - 8a - 64
Sum
Solution
2a2 - 8a - 64 = 2[a2 - 4a - 32]
= 2[a2 - 8a + 4a - 32]
= 2[a(a - 8) + 4(a - 8)]
= 2[(a - 8) (a + 4)]
= 2(a - 8)(a + 4)
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Factorising Completely
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