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Factorise the expression and divide them as directed. 39y3(50y2 − 98) ÷ 26y2(5y + 7) - Mathematics

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प्रश्न

Factorise the expression and divide them as directed.

39y3(50y2 − 98) ÷ 26y2(5y + 7)

योग

उत्तर

39y3(50y2 − 98) ÷ 26y2(5y + 7) 

`(39y^3(50y^2−98))/(26y^2(5y+7))` 

= `(39y^3×2(25y^2−49))/(26y^2(5y+7))`

= `(2*3*13y^3 (5y)^2 - 7^2)/(2*13y^2 (5y + 7))`

= `(3y (5y + 7) (5y - 7))/((5y + 7))`

= 3y (5y − 7)

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अध्याय 14: Factorisation - Exercise 14.3 [पृष्ठ २२७]

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एनसीईआरटी Mathematics [English] Class 8
अध्याय 14 Factorisation
Exercise 14.3 | Q 5.7 | पृष्ठ २२७

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