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प्रश्न
Factorise the expression and divide them as directed.
39y3(50y2 − 98) ÷ 26y2(5y + 7)
उत्तर
39y3(50y2 − 98) ÷ 26y2(5y + 7)
`(39y^3(50y^2−98))/(26y^2(5y+7))`
= `(39y^3×2(25y^2−49))/(26y^2(5y+7))`
= `(2*3*13y^3 (5y)^2 - 7^2)/(2*13y^2 (5y + 7))`
= `(3y (5y + 7) (5y - 7))/((5y + 7))`
= 3y (5y − 7)
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