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प्रश्न
Factorise the following:
`1/x^2 + 1/y^2 + 2/(xy)`
योग
उत्तर
`1/x^2 + 1/y^2 + 2/(xy) = (1/x)^2 + (1/y)^2 + 2(1/x) xx 1/y`
= `(1/x + 1/y)^2` ...[a2 + b2 + 2ab = (a + b)2]
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