Advertisements
Advertisements
प्रश्न
Factorise the following expression.
a2b + a2c + ab + ac + b2c + c2b
योग
उत्तर
We have,
a2b + a2c + ab + ac + b2c + c2b
= (a2b + ab + b2c) + (a2c + ac + c2b)
= b(a2 + a + bc) + c(a2 + a + bc)
= (a2 + a + bc)(b + c)
shaalaa.com
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 7: Algebraic Expression, Identities and Factorisation - Exercise [पृष्ठ २३४]
APPEARS IN
संबंधित प्रश्न
Constant is only 8 other is variable 5 + 2a - 3b
For the following monomials, write its degree: – 9y2z3
Write the degree of the following polynomial: 2y2z + 9yz3
Write numerical co-efficient of the following: - y
Fill in the blank:
The sum of 8a, 6a and 5b = _______.
Add : 23y2 , 8y2 and – 12y2
Find the numerical co-efficient of the following term:
121bc
Common factor of 12a2b2 + 4ab2 – 32 is 4.
Write the greatest common factor in the following terms.
3x2y, 18xy2, – 6xy
Write the greatest common factor in the following terms.
13x2y, 169xy
