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प्रश्न
Factorise the following expression.
ax2y – bxyz – ax2z + bxy2
योग
उत्तर
We have,
ax2y – bxyz – ax2z + bxy2
= x(axy – byz – axz + by2)
= x(axy – axz – byz + by2)
= x[ax(y – z) + by(–z + y)]
= x[(ax + by)(y – z)]
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अध्याय 7: Algebraic Expression, Identities and Factorisation - Exercise [पृष्ठ २३४]
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