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प्रश्न
Factorise the following expression.
y2 + 8zx – 2xy – 4yz
योग
उत्तर
We have,
y2 + 8zx – 2xy – 4yz
= y2 – 2xy + 8zx – 4yz
= y(y – 2x) – 4z(y – 2x)
= (y – 2x)(y – 4z)
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अध्याय 7: Algebraic Expression, Identities and Factorisation - Exercise [पृष्ठ २३४]
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