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प्रश्न
Factorise the following, using the identity a2 – 2ab + b2 = (a – b)2.
`9y^2 - 4xy + (4x^2)/9`
योग
उत्तर
We have,
`9y^2 - 4xy + (4x^2)/9 = (3y)^2 - 2 * 3y * 2/3x + (2/3x)^2`
= `(3y - 2/3x)^2`
= `(3y - (2x)/3)(3y - (2x)/3)`
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अध्याय 7: Algebraic Expression, Identities and Factorisation - Exercise [पृष्ठ २३५]
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