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Factorize Each of the Following Quadratic Polynomials by Using the Method of Completing the Square: A2 − 14a − 51 - Mathematics

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प्रश्न

Factorize each of the following quadratic polynomials by using the method of completing the square:
a2 − 14a − 51

योग

उत्तर

\[a^2 - 14a - 51\]
\[ = a^2 - 14a + \left( \frac{14}{2} \right)^2 - \left( \frac{14}{2} \right)^2 - 51 [\text{ Adding and subtracting }\left( \frac{14}{2} \right)^2 ,\text{ that is }, 7^2 ]\]
\[ = a^2 - 14a + 7^2 - 7^2 - 51\]
\[ = (a - 7 )^2 - 100 [\text{ Completing the square }]\]
\[ = (a - 7 )^2 - {10}^2 \]
\[ = [(a - 7) - 10][(a - 7) + 10]\]
\[ = (a - 7 - 10)(a - 7 + 10)\]
\[ = (a - 17)(a + 3)\]
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अध्याय 7: Factorization - Exercise 7.9 [पृष्ठ ३२]

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आरडी शर्मा Mathematics [English] Class 8
अध्याय 7 Factorization
Exercise 7.9 | Q 6 | पृष्ठ ३२

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