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Factorize the following polynomial. (y + 2) (y – 3) (y + 8) (y + 3) + 56 - Algebra

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प्रश्न

Factorize the following polynomial.

(y + 2) (y – 3) (y + 8) (y + 3) + 56 

योग

उत्तर

(y + 2) (y – 3) (y + 8) (y + 3) + 56 

= (y + 2) (y + 3) (y + 8) (y – 3) + 56

= (y2 + 3y + 2y + 6) (y2 + 8y - 3y - 24) + 56

= (y2 + 5y + 6) (y2 + 5y – 24) + 56

Let y2 + 5y = z

∴ (y2 + 5y + 6) (y2 + 5y - 24) + 56

= (z + 6 ) (z - 24) + 56

= z2 - 24z + 6z - 144 + 56

= z2 - 18z - 144 + 56

= z2 - 18z - 88

= z2 - 22z + 4z - 88

= z (z - 22) + 4 (z - 22)

= (z - 22) (z + 4)

= (y2 + 5y - 22) (y2 + 5y + 4)   ...(Replace z = y2 + 5y)

= (y2 + 5y - 22) (y2 + 4y + y + 4)

= (y2 + 5y - 22) [y (y + 4) + 1 ( y + 4)] 

= (y2 + 5y - 22) (y + 4) (y + 1)

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Factorisation of Polynomials
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 3: Polynomials - Practice Set 3.6 [पृष्ठ ५५]

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बालभारती Algebra (Mathematics 1) [English] 9 Standard Maharashtra State Board
अध्याय 3 Polynomials
Practice Set 3.6 | Q (2) (v) | पृष्ठ ५५
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