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Figure 2.23 Show the Graph of the Polynomial F(X) = Ax2 + Bx + C for Which - Mathematics

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प्रश्न

Figure 2.23 show the graph of the polynomial f(x) = ax2 + bx + c for which 

विकल्प

  • a < 0, b > 0 and c > 0

  • a < 0, b < 0 and c > 0

  • a < 0, b < 0 and c < 0

  • a > 0, b > 0 and c < 0

MCQ

उत्तर

Clearly, f(x) = ax2 + bx + c represent a parabola opening downwards. Therefore, `a < 0`

` y= ax^2 + bx + c `  cuts y-axis at P which lies on `OY`. Putting x = 0 in ` y = ax^2 + bx + c `, we get y =c. So the coordinates P are `(0,c)`. Clearly, P lies on `(OY)`. Therefore  `c > 0`

The vertex  `(-b)/(2a), (-D)/(4a)` of the parabola is in the second quadrant. Therefore `-b /(2a)`, `b < 0`

Therefore `a < 0,b>0` and `c > 0`

Hence, the correct choice is `(b)`

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 2: Polynomials - Exercise 2.5 [पृष्ठ ६१]

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आरडी शर्मा Mathematics [English] Class 10
अध्याय 2 Polynomials
Exercise 2.5 | Q 10 | पृष्ठ ६१

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