Advertisements
Advertisements
प्रश्न
Figure shows the position of vernier scale while measuring the external length of a wooden cylinder.
- What is the length recorded by the main scale?
- Which reading of vernier scale coincides with the main scale?
- Calculate the length.
उत्तर
Main scale divisions of vernier callipers in one centimetre = 10
Pitch = `"Unit of main scale"/"Number of divisions in the unit"`
= `1/10` cm = 0.1 cm
Least count = `"Pitch"/"No. of divisions on the vernier scale"`
L.C. = `0.1/10` cm = 0.01 cm
1. Length recorded by main scale = 10.2 cm
⇒ Main scale reading is 10.2 cm
2. Reading of vernier scale coinciding with main scale = 7th
⇒ Vernier scale division (V.S.D.) is 7th
3. Length recorded by vernier callipers
= Main scale reading + L.C. × V.S.D.
= 10.2 + 0.01 × 7
= 10.2 + 0.07
= 10.27 cm
APPEARS IN
संबंधित प्रश्न
Define the least count of vernier callipers. How do you determine it?
What is meant by zero error of vernier callipers ? How is it determined? Draw neat diagrams to explain it. How is it taken in account to get the correct measurement?
Draw a neat and labelled diagram of a screw gauge.
Name its main parts and state their functions.
State one use of a screw gauge.
State the formula for determining a pitch
Figure shows a screw gauge in which circular scale has 100 divisions. Calculate the least count and the diameter of a wire.
Name the measuring employed to measure the thickness of a paper.
State whether the following statement is true or false by writing T/F against it.
The least count of a screw gauge can be lowered by increasing the number of divisions on its thimble.
What is the least count in the case of the following instrument?
vernier calipers