Advertisements
Advertisements
प्रश्न
Figure shows the position of vernier scale while measuring the external length of a wooden cylinder.
- What is the length recorded by the main scale?
- Which reading of vernier scale coincides with the main scale?
- Calculate the length.
उत्तर
Main scale divisions of vernier callipers in one centimetre = 10
Pitch = `"Unit of main scale"/"Number of divisions in the unit"`
= `1/10` cm = 0.1 cm
Least count = `"Pitch"/"No. of divisions on the vernier scale"`
L.C. = `0.1/10` cm = 0.01 cm
1. Length recorded by main scale = 10.2 cm
⇒ Main scale reading is 10.2 cm
2. Reading of vernier scale coinciding with main scale = 7th
⇒ Vernier scale division (V.S.D.) is 7th
3. Length recorded by vernier callipers
= Main scale reading + L.C. × V.S.D.
= 10.2 + 0.01 × 7
= 10.2 + 0.07
= 10.27 cm
APPEARS IN
संबंधित प्रश्न
Name the part of the vernier callipers which is used to measure the following
Thickness of a pencil.
When a screw gauge with a least count of 0.01 mm is used to measure the diameter of a wire, the reading on the sleeve is found to be 1 mm and the reading on the thimble is found to be 27 divisions.
(i) What is the diameter of the wire in cm?
(ii) If the zero error is +0.005 cm, what is the correct diameter?
A screw has a pitch equal to 0.5 mm. What should be the number of divisions on its head so as to read correctly up to 0.001 mm with its help?
A pendulum completes 2 oscillations in 5 s. What is its time period? If g = 9.8 m s-2, find its length.
State the formula for calculating length if:
The reading of the main scale is known and the number of vernier scale divisions coinciding with the main scale is known.
When does a vernier callipers has the negative error?
Explain the term least count of a screw gauge. How are they determined?
State whether the following statement is true or false by writing T/F against it.
The metre scale, vernier calipers, and screw gauge are in decreasing order of least count.
