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प्रश्न
A pendulum completes 2 oscillations in 5 s. What is its time period? If g = 9.8 m s-2, find its length.
उत्तर
Time period = Total time/total no. of oscillations
= (5/2) s
= 2.5 s
Let 'l' be the length. Then,
`T = 2pisqrt(l/"g")`
or , `2.5 = 2(3.14)sqrt(l/9.8)`
or , 0.398 = `sqrt(l/9.8)`
or , `l = (0.398)^2(9.8)`
or , l = 1.55 m
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संबंधित प्रश्न
The least count of a vernier calipers is :
The pitch of a screw gauge is 1 mm and the circular scale has 100 divisions. In measurement of the diameter of a wire, the main scale reads 2 mm and 45th mark on the circular scale coincides with the base line. Find
(i) The least count and
(ii) The diameter of the wire.
When a screw gauge with a least count of 0.01 mm is used to measure the diameter of a wire, the reading on the sleeve is found to be 1 mm and the reading on the thimble is found to be 27 divisions.
(i) What is the diameter of the wire in cm?
(ii) If the zero error is +0.005 cm, what is the correct diameter?
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Which part of vernier callipers is used to measure the external diameter of a cylinder?
Figure shows a screw gauge in which circular scale has 100 divisions. Calculate the least count and the diameter of a wire.
What do you understand by the following term as applied to micrometre screw gauge?
Sleeve cylinder
What do you understand by the following term as applied to micrometre screw gauge?
Thimble
A vernier caliper using the scale invented by Galileo.
