Advertisements
Advertisements
Question
A pendulum completes 2 oscillations in 5 s. What is its time period? If g = 9.8 m s-2, find its length.
Solution
Time period = Total time/total no. of oscillations
= (5/2) s
= 2.5 s
Let 'l' be the length. Then,
`T = 2pisqrt(l/"g")`
or , `2.5 = 2(3.14)sqrt(l/9.8)`
or , 0.398 = `sqrt(l/9.8)`
or , `l = (0.398)^2(9.8)`
or , l = 1.55 m
APPEARS IN
RELATED QUESTIONS
The least count of a vernier callipers is 0.0025 cm and it has an error of + 0.0125 cm. While measuring the length of a cylinder, the reading on the main scale is 7.55 cm, and the 12th vernier scale division coincides with the main scale. Calculate the corrected length.
Who invented vernier callipers?
The thimble of a screw gauge has 50 divisions for one rotation. The spindle advances 1 mm when the screw is turned through two rotations.
- What is the pitch of the screw?
- What is the least count of screw gauge?
- When the screw gauge is used to measure the diameter of wire the reading on the sleeve is found to be 0.5 mm and reading on thimble is found, 27 divisions. What is the diameter of the wire in centimetres?
State the formula for calculating the pitch of screw.
What is the least count in the case of the following instrument?
Stopwatch
Consider the following case where the zero of vernier scale and the zero of the main scale are clearly seen. If L.C. of the vernier calipers is 0.01 cm, write the zero error and zero correction of the following.
What is meant by the pitch of a screw gauge? The pitch of a screw is 1 mm.
Find the reading of the instrument shown in the following figure.
