Advertisements
Advertisements
प्रश्न
The time periods of two simple pendulums at a place are in the ratio 2:1. What will be the corresponding ratio of their lengths?
उत्तर
Let T1 and T2 be the time periods of the two pendulums of lengths l1 and l2, respectively.
Then, we know that the time period is directly proportional to the square root of the length of the pendulum.
∴ `T_1/T_2 = sqrt(l_1/l_2)`
or , `l_1/l_2 = (T_1/T_2)^2`
or , `l_1/l_2 = (2/1)^2 = 4 : 1`
APPEARS IN
संबंधित प्रश्न
How are the time period T and frequency f of an oscillation of a simple pendulum related ?
Compare the time periods of the two pendulums of lengths 1 m and 9 m.
Length of the second’s pendulum is 100 cm. Find the length of another pendulum whose time period is 2.4 s.
Amongst the independent variable and dependent variable, which is plotted on X-axis?
What does the best fit line show regarding the variables plotted and the work of the experimenter?
What do you understand by the term constant of proportionality?
Complete the rollowing:
1 light year= ________ m