Advertisements
Advertisements
प्रश्न
Length of the second’s pendulum is 100 cm. Find the length of another pendulum whose time period is 2.4 s.
उत्तर
We know the time period of the second’s pendulum is 2 s.
∴ T1 = 2 s, l1 = 100 cm
T2 = 2.4 s, l2 = ?
`"T"_1/"T"_2=sqrt("l"_1/"l"_2)`
`2/2.4=sqrt(100/"l"_2)`
`1/1.2=sqrt(100/"l"_2)`
Squaring both sides,
`1/1.44=100/"l"_2`
l2 = 100 × 1.44 = 144 cm
APPEARS IN
संबंधित प्रश्न
Name two factors on which the time period of a simple pendulum does not depend.
The time period of a simple pendulum is 2 s. What is its frequency? What name is given to such a pendulum?
How much time does the bob of a second's pendulum take to move from one extreme of its oscillation to the other extreme?
A second’s pendulum is taken on the surface of the moon where the acceleration due to gravity is l/6th of that of earth. Will the time period of pendulum remain the same or increase or decrease? Give a reason.
Moon has no atmosphere and acceleration due to gravity at its surface is one-sixth that at the earth's surface. When a pendulum is taken from earth to moon surface, its time period will:
