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प्रश्न
Moon has no atmosphere and acceleration due to gravity at its surface is one-sixth that at the earth's surface. When a pendulum is taken from earth to moon surface, its time period will:
पर्याय
Increase
decrease
Not change
becomes infinite.
उत्तर
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संबंधित प्रश्न
How are the time period T and frequency f of an oscillation of a simple pendulum related ?
The time periods of two simple pendulums at a place are in the ratio 2:1. What will be the corresponding ratio of their lengths?
Calculate the time period of a simple pendulum of length 0. 84 m when g = 9.8 ms−2.
Length of the second’s pendulum is 100 cm. Find the length of another pendulum whose time period is 2.4 s.
A second’s pendulum is taken on the surface of the moon where the acceleration due to gravity is l/6th of that of earth. Will the time period of pendulum remain the same or increase or decrease? Give a reason.
Draw a graph of l, the length of simple pendulum against T2, the square of its time period.
State how will you choose a scale for the graph.
If a pendulum takes 0.5 s to travel from A to B as shown in the following figure, find its time period and frequency.
Name the factors on which the time period of a simple pendulum depends. Write the relation for the time period in terms of the above named factors.
