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Question
Length of the second’s pendulum is 100 cm. Find the length of another pendulum whose time period is 2.4 s.
Numerical
Solution
We know the time period of the second’s pendulum is 2 s.
∴ T1 = 2 s, l1 = 100 cm
T2 = 2.4 s, l2 = ?
`"T"_1/"T"_2=sqrt("l"_1/"l"_2)`
`2/2.4=sqrt(100/"l"_2)`
`1/1.2=sqrt(100/"l"_2)`
Squaring both sides,
`1/1.44=100/"l"_2`
l2 = 100 × 1.44 = 144 cm
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