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Question
A pendulum of length 36 cm has a time period of 1.2 s. Find the time period of another pendulum, whose length is 81 cm.
Solution
l1 = 36 cm, T1 = 1.2 s
l2 = 81 cm, T2 = ?
`"T"_1/"T"_2=sqrt("l"_1/"l"_2)`
`1.2/"T"_2=sqrt(36/81)`
`1.2/"T"_2=6/9`
T2 = `(9xx1.2)/6` = 9 × 0.2 = 1.8 s
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