Find: Ad - Mathematics

Find: AD

योग

From the right triangle ABD

cos A = `"AD"/"AB"`

cos 60° = `"AD"/"AB"`

`(1)/(2) = "AD"/(12)`

AD = `(12)/(2)`

= 6 cm

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Solution of Right Triangles

क्या इस प्रश्न या उत्तर में कोई त्रुटि है?

अध्याय 24: Solution of Right Triangles [Simple 2-D Problems Involving One Right-angled Triangle] - Exercise 24 [पृष्ठ ३०४]

अध्याय 24 Solution of Right Triangles [Simple 2-D Problems Involving One Right-angled Triangle]
Exercise 24 | Q 13.2 | पृष्ठ ३०४

Find angle 'A' if :

Find AD, if:

In trapezium ABCD, as shown, AB // DC, AD = DC = BC = 20 cm and A = 60^°. Find: distance between AB and DC.

In the given figure, AB and EC are parallel to each other. Sides AD and BC are 2 cm each and are perpendicular to AB.

Given that ∠ AED = 60° and ∠ ACD = 45°. Calculate: AB.

In the given figure, AB and EC are parallel to each other. Sides AD and BC are 2 cm each and are perpendicular to AB.

Given that ∠ AED = 60° and ∠ ACD = 45°. Calculate: AE.

Find: BC

Find: AC

In right-angled triangle ABC; ∠B = 90°. Find the magnitude of angle A, if:
BC is `sqrt(3)` times of AB.

Find AB and BC, if:

Find PQ, if AB = 150 m, ∠P = 30° and ∠Q = 45°.