Advertisements
Advertisements
प्रश्न
Find the roots of the quadratic equations 2x2 + x + 4 = 0 by applying the quadratic formula.
उत्तर
2x2 + x + 4 = 0
On comparing this equation with ax2 + bx + c = 0, we get
a = 2, b = 1 and c = 4
By using quadratic formula, we get
`x = (-b±sqrtb2 - 4ac)/(2a)`
`⇒ x = (-1±sqrt(1-32))/4`
`⇒ x = (-1±sqrt(-31))/4`
The square of a number can never be negative.
∴There is no real solution of this equation.
APPEARS IN
संबंधित प्रश्न
Find the roots of the following equations:
`x-1/x = 3, x ≠ 0`
The length of a rectangle is thrice as long as the side of a square. The side of the square is 4 cm more than the width of the rectangle. Their areas being equal, find the dimensions.
The length of the hypotenuse of a right-angled triangle exceeds the length of the base by 2 cm and exceeds twice the length of the altitude by 1 cm. Find the length of each side of the triangle.
Solve the following quadratic equation by completing the square method.
x2 + 2x – 5 = 0
The sum of the squares of two consecutive odd numbers is 394. Find the numbers.
The sum of the squares of two consecutive multiples of 7 is 637. Find the multiples.
The sum of the squares of two consecutive even numbers is 340. Find the numbers.
The numerator of a fraction is 3 less than the denominator. If 2 is added to both the numerator and the denominator, then the sum of the new fraction and the original fraction is \[\frac{29}{20}\].Find the original fraction.
A chess board contains 64 equal squares and the area of each square is 6.25 cm2. A border round the board is 2 cm wide. The length of the side of the chess board is:
Find the remainder when p(x) = 3x2 + 2x – 7 is divided by 2x + 1.