Advertisements
Advertisements
प्रश्न
Find the roots of the quadratic equations `4x^2+4sqrt3x + 3 = 0` by applying the quadratic formula.
उत्तर
`4x^2 + 4sqrt3x + 3 = 0`
On comparing this equation with ax2 + bx + c = 0, we get
a = 4, b = ` 4sqrt3` and c = 3
By using quadratic formula, we get
`x = (-b±sqrtb2 - 4ac)/(2a)`
`⇒ x = (-4sqrt3±sqrt48-48)/8`
`⇒ x = (-4sqrt3±0)/8`
`∴ x = (-sqrt3)/2 `
APPEARS IN
संबंधित प्रश्न
Find the roots of the quadratic equation 4x2 + 4√3x + 3 = 0
Find the roots of the following quadratic equations (if they exist) by the method of completing the square.
`x^2-4sqrt2x+6=0`
`x^2-(sqrt2+1)x+sqrt2=0`
By using the method of completing the square, show that the equation `2x^2+x+4=0` has no real roots.
The area of a right triangle is `600cm^2` . If the base of the triangle exceeds the altitude by 10 cm, find the dimensions of the triangle.
Sum of the areas of two squares is 400 cm2. If the difference of their perimeters is 16 cm, find the sides of the two squares ?
Fill in the gap and complete.
α, β are roots of y2 – 2y –7 = 0 find,
α3 + β3
The sum of the squares of two consecutive even numbers is 340. Find the numbers.
Find the remainder when p(x) = 3x2 + 2x – 7 is divided by 2x + 1.