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Question
Find the roots of the quadratic equations `4x^2+4sqrt3x + 3 = 0` by applying the quadratic formula.
Solution
`4x^2 + 4sqrt3x + 3 = 0`
On comparing this equation with ax2 + bx + c = 0, we get
a = 4, b = ` 4sqrt3` and c = 3
By using quadratic formula, we get
`x = (-b±sqrtb2 - 4ac)/(2a)`
`⇒ x = (-4sqrt3±sqrt48-48)/8`
`⇒ x = (-4sqrt3±0)/8`
`∴ x = (-sqrt3)/2 `
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