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प्रश्न
Find the 9th term of the series :
1, 4, 16, 64, ...............
उत्तर
Given sequence: 1, 4, 16, 64, ...............
Now,
`4/1 = 4, 16/4 = 4, 64/16 = 4`
Since `4/1 = 16/4 = 64/16 = ...... = 4,` the given sequence is a G.P. with the first term, a = 1 and common ratio, r = 4.
Now, Tn = arn – 1
`\implies` T9 = 1 × 49 – 1
= 1 × 48
= 48
= 4 × 4 × 4 × 4 × 4 × 4 × 4 × 4
= 65536
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