Advertisements
Advertisements
प्रश्न
Find the area of triangles whose vertices are A(−1, 2), B(2, 4), C(0, 0).
उत्तर
Here, A(x1, y1) ≡ A(–1, 2), B(x2, y2) ≡ B(2, 4), C(x3, y3) ≡ C(0, 0)
Area of a triangle = `1/2|(x_1, y_1, 1),(x_2, y_2, 1),(x_3, y_3, 1)|`
∴ A(ΔABC) = `1/2|(-1, 2, 1),(2, 4, 1),(0, 0, 1)|`
= `1/2[-1(4 - 0) - 2(2 - 0) + 1(0 - 0)]`
= `1/2(-4 - 4)`
= `1/2(- 8)`
= –4
Since the area cannot be negative.
∴ A(ΔABC) = 4 sq. units
APPEARS IN
संबंधित प्रश्न
Find the area of the triangle whose vertices are: (0, 5), (0, – 5), (5, 0)
Find the value of k, if the area of the triangle with vertices at A(k, 3), B(–5, 7), C(–1, 4) is 4 square units.
Find the area of the quadrilateral whose vertices are A(–3, 1), B(–2, –2), C(4, 1), D(2, 3).
Find the area of triangles whose vertices are P(3, 6), Q(−1, 3), R(2, −1)
Find the value of k, if area of ΔLMN is `33/2` square units and vertices are L(3, − 5), M(− 2, k), N(1, 4).
Find the values of 'K' if area of triangle is 4 square units and vertices are (k, 0), (4, 0), (0, 2).
If the area of triangle is 35 square units with vertices (2, – 6), (5, 4) and (k, 4) then k is
Find the area of triangle whose vertices are A ( -1,2) ,B (2,4) ,C (0,0)
Find the area of triangle whose vertices are A( -1, 2), B(2, 4), C(0, 0)
Find the area of triangle whose vertices are A(-1,2), B(2,4), C(0,0)
Find the area of triangle whose vertices are A( -1, 2), B(2, 4), C(0, 0).
Find the area of triangle whose vertices are A(-1, 2), B(2, 4), C(0, 0).
Find the area of triangle whose vertice are A(-1, 2), B(2, 4), C(0, 0)
Find the area of triangle whose vertices are A(-1, 2), B(2, 4), C(0, 0)
Find the area of triangle whose vertices are A(-1, 2), B(2, 4), C(0, 0).
Find the area of triangle whose vertices are A(−1, 2), B(2, 4), C(0, 0)
Find the area of triangle whose vertices are A (-1, 2), B (2, 4), C (0, 0).
Find the area of triangles whose vertices are A(−1, 2), B(2, 4), C(0, 0).
