Advertisements
Advertisements
प्रश्न
Find the area of triangles whose vertices are P(3, 6), Q(−1, 3), R(2, −1)
उत्तर
Here, P(x1, y1) ≡ P(3, 6), Q(x2, y2) ≡ Q(−1, 3), R(x3, y3) ≡ R(2, −1)
Area of triangle = `1/2|(x_1, y_1, 1),(x_2, y_2, 1),(x_3, y_3, 1)|`
∴ A(ΔPQR) = `1/2|(3, 6, 1),(-1, 3, 1),(2, -1, 1)|`
= `1/2[3(3 + 1) - 6(-1 - 2) + 1(1 - 6)]`
= `1/2[3(4) - 6(- 3) + 1( - 5)]`
= `1/2(12 + 18 - 5)`
∴ A(ΔPQR) = `25/2` sq. units
APPEARS IN
संबंधित प्रश्न
Find the area of the triangle whose vertices are: (3, 2), (–1, 5), (–2, –3)
Find the area of the triangle whose vertices are: (0, 5), (0, – 5), (5, 0)
Find the area of the quadrilateral whose vertices are A(–3, 1), B(–2, –2), C(4, 1), D(2, 3).
Find the area of triangles whose vertices are A(−1, 2), B(2, 4), C(0, 0).
What will the equation of line joining (1, 2) and (3, 6) using determinants
Find the area of triangle whose vertices are A ( -1,2), B (2,4), C (0,0)
Find the area of triangle whose vertices are A( -1, 2), B(2, 4), C(0, 0)
Find the area of triangle whose vertices are A(-1,2), B(2,4), C(0,0)
Find the area of triangle whose vertices are A( -1, 2), B(2, 4), C(0, 0).
Find the area of triangle whose vertices are A(−1, 2), B(2, 4), C(0, 0).
Find the area of triangle whose vertices are A(-1, 2), B(2, 4), C(0, 0).
Find the area of triangle whose vertice are A(-1, 2), B(2, 4), C(0, 0)
Find the area of triangle whose vertices are A(-1, 2), B(2, 4), C(0, 0).
Find the area of triangle whose vertices are A(−1, 2), B(2, 4), C(0, 0)
Find the area of triangle whose vertices are A (-1, 2), B (2, 4), C (0, 0).
