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प्रश्न
Find the coordinates of the centroid P of the ΔABC, whose vertices are A(–1, 3), B(3, –1) and C(0, 0). Hence, find the equation of a line passing through P and parallel to AB.
योग
उत्तर
(a) `P((-1 + 3 + 0)/3, (3 +(-1) + 0)/3) = P(2/3, 2/3)`
(b) mAB = `(-1 - (3))/(3 - (-1))`
= `(-4)/4`
= –1
mAB = –1
Required equation,
`y - 2/3 = -1(x - 2/3)`
`\implies` 3x + 3y = 4
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Centroid of a Triangle
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संबंधित प्रश्न
The coordinates of the vertices of ΔABC are respectively (–4, –2), (6, 2) and (4, 6). The centroid G of ΔABC is ______.
In the given diagram, ABC is a triangle, where B(4, – 4) and C(– 4, –2). D is a point on AC.
- Write down the coordinates of A and D.
- Find the coordinates of the centroid of ΔABC.
- If D divides AC in the ratio k : 1, find the value of k.
- Find the equation of the line BD.
