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प्रश्न
Find the equation of a straight line which has slope `(−5)/4` and passing through the point (– 1, 2).
उत्तर
Slope of a line (m) = `(−5)/4`
The given point (x1, y1) = (−1, 2)
Equation of a line is y – y1 = m (x – x1)
y – 2 = `(-5)/4(x + 1)`
5(x + 1) = − 4(y – 2)
5x + 5 = − 4y + 8
5x + 4y + 5 – 8 = 0
5x + 4y – 3 = 0
The equation of a line is 5x + 4y – 3 = 0
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