Advertisements
Advertisements
प्रश्न
Find the equation of a straight line passing through (– 8, 4) and making equal intercepts on the coordinate axes
उत्तर
Let the x-intercept andy intercept “a”
The equation of a line is
`x/"a" + y/"a"` = 1
The line passes through the point (– 8, 4)
`(-8)/"a" + 4/"a"` = 1
`(-8 + 4)/"a"` = 1
– 4 = a
The equation of a line is
`x/(-4) + y/(-4)` = 1
Multiply by – 4
x + y = – 4
x + y + 4 = 0
The equation of the line is x + y + 4 = 0
APPEARS IN
संबंधित प्रश्न
The equation of a straight line is 2(x – y) + 5 = 0. Find its slope, inclination and intercept on the Y-axis
Find the equation of a line whose inclination is 30˚ and making an intercept –3 on the Y-axis.
Find the value of ‘a’, if the line through (– 2, 3) and (8, 5) is perpendicular to y = ax + 2
The hill in the form of a right triangle has its foot at (19, 3). The inclination of the hill to the ground is 45°. Find the equation of the hill joining the foot and top.
Find the equation of a line through the given pair of point `(2,2/3)` and `((-1)/2, -2)`
Find the equation of the median and altitude of ΔABC through A where the vertices are A(6, 2), B(– 5, – 1) and C(1, 9)
Find the equation of a straight line which has slope `(−5)/4` and passing through the point (– 1, 2).
Find the equation of a line whose intercepts on the x and y axes are given below
4, – 6
Find the equation of a straight line passing through (1, – 4) and has intercepts which are in the ratio 2 : 5
The point of intersection of 3x – y = 4 and x + 7 = 8 is
