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प्रश्न
Find the equation of a line whose intercepts on the x and y axes are given below
4, – 6
उत्तर
x intercept (a) = 4, y intercept (b) = – 6
Equation of a line is `x/"a" + y/"b"` = 1
`x/4 + y/(-6)` = 1
⇒ `x/4 - y/6` = 1 ...(L.C.M. of 4 and 6 is 12)
3x – 2y = 12
3x – 2y – 12 = 0
The equation of a line is 3x – 2y – 12 = 0
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