Advertisements
Advertisements
प्रश्न
Find the equation of a line whose intercepts on the x and y axes are given below
`- 5, 3/4`
उत्तर
x intercept (a) = – 5, y intercept (b) = `3/4`
Equation of a line is `x/"a" + y/"b"` = 1
⇒ `x/(-5) + y/(3/4)` = 1
`x/(-5) + (4y)/3` = 1 ...(L.C.M. of 5 and 3 is 15)
– 3x + 20y = 15
– 3x + 20y – 15 = 0
3x – 20y + 15 = 0
∴ Equation of a line is 3x – 20y + 15 = 0
APPEARS IN
संबंधित प्रश्न
Find the equation of a straight line passing through the mid-point of a line segment joining the points (1, – 5), (4, 2) and parallel to Y-axis
The equation of a straight line is 2(x – y) + 5 = 0. Find its slope, inclination and intercept on the Y-axis
Find the equation of a line whose inclination is 30˚ and making an intercept –3 on the Y-axis.
Find the value of ‘a’, if the line through (– 2, 3) and (8, 5) is perpendicular to y = ax + 2
Find the equation of a line through the given pair of point `(2,2/3)` and `((-1)/2, -2)`
Find the equation of a line through the given pair of point (2, 3) and (– 7, – 1)
Find the equation of a straight line which has slope `(−5)/4` and passing through the point (– 1, 2).
You are downloading a song. The percent y (in decimal form) of megabytes remaining to get downloaded in x seconds is given by y = – 0.1x + 1 after how many seconds the song will be downloaded completely?
Find the equation of a straight line passing through (– 8, 4) and making equal intercepts on the coordinate axes
(2, 1) is the point of intersection of two lines
