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तमिलनाडु बोर्ड ऑफ सेकेंडरी एज्युकेशनएसएसएलसी (अंग्रेजी माध्यम) कक्षा १०

If A is a point on the Y axis whose ordinate is 8 and B is a point on the X axis whose abscissae is 5 then the equation of the line AB is - Mathematics

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प्रश्न

If A is a point on the Y-axis whose ordinate is 8 and B is a point on the X-axis whose abscissae is 5 then the equation of the line AB is

विकल्प

  • 8x + 5y = 40

  • 8x – 5y = 40

  • x = 8

  • y = 5

MCQ

उत्तर

8x + 5y = 40

Explanation;

Hint:

Let point A be (0, 8) and B (5, 0)

`(y - y_1)/(y_2 - y_1) = (x - x_1)/(x_2 - x_1)`

`(y - 8)/(0 - 8) = (x - 0)/(5 - 0)`

⇒ `(y - 8)/(-8) = x/5`

− 8x = 5y = − 40

− 8x − 5y = − 40

8x + 5y = 40

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 5: Coordinate Geometry - Exercise 5.5 [पृष्ठ २३६]

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सामाचीर कलवी Mathematics [English] Class 10 SSLC TN Board
अध्याय 5 Coordinate Geometry
Exercise 5.5 | Q 9 | पृष्ठ २३६
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