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प्रश्न
If A is a point on the Y-axis whose ordinate is 8 and B is a point on the X-axis whose abscissae is 5 then the equation of the line AB is
पर्याय
8x + 5y = 40
8x – 5y = 40
x = 8
y = 5
उत्तर
8x + 5y = 40
Explanation;
Hint:
Let point A be (0, 8) and B (5, 0)
`(y - y_1)/(y_2 - y_1) = (x - x_1)/(x_2 - x_1)`
`(y - 8)/(0 - 8) = (x - 0)/(5 - 0)`
⇒ `(y - 8)/(-8) = x/5`
− 8x = 5y = − 40
− 8x − 5y = − 40
8x + 5y = 40
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