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Find the equation of the lines passing through the point (1,1) and (– 2, 3) - Mathematics

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प्रश्न

Find the equation of the lines passing through the point (1,1) and (– 2, 3)

योग

उत्तर

The equation of line joining the two points (x1, y1) and (x2, y2) is

`(y - y_1)/(y_2 - y_1) = (x - 1)/(– 2 – 1)`

Given (x1, y1) = (1, 1), (x2, y2) = (– 2, 3)

∴ The equation of the required line is

`(y - 1)/(3 - 1) = (x - 1)/(- 2 - 1)`

`(y - 1)/2 = (x - 1)/( - 3)`

– 3(y – 1) = 2(x – 1)

– 3y + 3 = 2x – 2

2x + 3y – 2 – 3 = 0

2x + 3y – 5 = 0

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अध्याय 6: Two Dimensional Analytical Geometry - Exercise 6.2 [पृष्ठ २६०]

APPEARS IN

सामाचीर कलवी Mathematics - Volume 1 and 2 [English] Class 11 TN Board
अध्याय 6 Two Dimensional Analytical Geometry
Exercise 6.2 | Q 1. (iii) | पृष्ठ २६०

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