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प्रश्न
Find the general solution of tan2θ = 1.
योग
उत्तर
We have tan2θ = 1
∴ `tan^2θ = tan^2 pi/4`
The general solution of tan2θ = α is θ = nπ ± α, where n ∈ Z.
∴ The general solution of tan2θ = `tan^2 pi/4` is θ = `npi ± pi/4`, where n ∈ Z.
∴ The general solution of tan2θ = 1 is θ = `npi ± pi/4`, where n ∈ Z.
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