Advertisements
Advertisements
प्रश्न
Find the least positive value of k for which the equation x2 + kx + 4 = 0 has real roots.
उत्तर
x2 + kx + 4 = 0
Here, a = 1, b = k, c = 4
b2 - 4ac
= k2 - 4 x 1 x 4
= k2 - 16
∵ Roots are real and positive.
∴ k2 - 16 ≥ 0
⇒ k2 ≥ 16
⇒ k ≥ 4
⇒ k = 4.
APPEARS IN
संबंधित प्रश्न
If x=−`1/2`, is a solution of the quadratic equation 3x2+2kx−3=0, find the value of k
Find that non-zero value of k, for which the quadratic equation kx2 + 1 − 2(k − 1)x + x2 = 0 has equal roots. Hence find the roots of the equation.
If a, b, c are real numbers such that ac ≠ 0, then show that at least one of the equations ax2 + bx + c = 0 and -ax2 + bx + c = 0 has real roots.
Write the value of k for which the quadratic equation x2 − kx + 4 = 0 has equal roots.
Write the discriminant of the quadratic equation (x + 5)2 = 2 (5x − 3).
In the quadratic equation kx2 − 6x − 1 = 0, determine the values of k for which the equation does not have any real root.
(3x - 5)(2x + 7) = 0
Find the value of k for which the following equation has equal roots:
(k − 12)x2 + 2(k − 12)x + 2 = 0.
Without solving the following quadratic equation, find the value of 'm' for which the given equation has real and equal roots.
x2 + 2(m – 1)x + (m + 5) = 0
Find whether the following equation have real roots. If real roots exist, find them.
`x^2 + 5sqrt(5)x - 70 = 0`