Advertisements
Advertisements
प्रश्न
Find the median of the 10 observations 36, 33, 45, 28, 39, 45, 54, 23, 56, 25. If another observation 35 is added to the above data, what would be the new median?
उत्तर
Arranging the given 10 observations in ascending order 23, 25, 28, 33, 36, 39, 45, 45, 54, 56
Here number of data n = 10, which is even
∴ Median = `1/2{("n"/2)^"th" "term" + ("n"/2 + 1)^"th" "term"}`
= `1/2{(10/2)^"th" "term" + (10/2 + 1)^"th" "term"}`
= `1/2{5^"th" "term" + 6^"th" "term"}`
= `1/2{36 + 39}`
= `1/2(75)`
= 37.5
∴ Median = 37.5
If 35 is added to the above data then it will be the 5th term then number of data n = 11, which is odd
∴ Median = `(("n" + 1)/2)^"th"` term
= `((11 + 1)/2)^"th"` term
= `(12/2)^"th"` term
= 6th term
New median = 36
APPEARS IN
संबंधित प्रश्न
Find the mean (correct to one place of decimal) by using short-cut method.
|
x |
40 |
41 |
43 |
45 |
46 |
49 |
50 |
|
f |
14 |
28 |
38 |
50 |
40 |
20 |
10 |
Q 11
The heights of 9 persons are 142 cm, 158 cm, 152 cm, 143 cm, 139 cm, 144 cm, 146 cm, 148 cm and 151 cm. Find the mean height.
The weights of 11 students in a class are 36 kg, 45 kg, 44 kg, 37 kg, 36 kg, 41 kg, 45 kg, 43 kg, 39 kg, 42 kg and 40 kg. Find the median of their weights.
Find the median of the following:
3x, x+5, x+7, x+9, x+11, x+13
The mean of a certain number of observations is 32. Find the resulting mean, if the observation is, multiplied by 2
The mean of marks scored by 100 students was found to be 40, later on, it was discovered that a score of 53 was misread as 83. Find the correct mean.
The mean of five numbers is 27. If one number is excluded, the mean of the remaining numbers is 25. Find the excluded number.
Find the mean of: first eight natural numbers
The median of the data 12, 14, 23, 25, 34, 11, 42, 45, 32, 22, 44 is ___________
