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प्रश्न
Find the median of the 10 observations 36, 33, 45, 28, 39, 45, 54, 23, 56, 25. If another observation 35 is added to the above data, what would be the new median?
उत्तर
Arranging the given 10 observations in ascending order 23, 25, 28, 33, 36, 39, 45, 45, 54, 56
Here number of data n = 10, which is even
∴ Median = `1/2{("n"/2)^"th" "term" + ("n"/2 + 1)^"th" "term"}`
= `1/2{(10/2)^"th" "term" + (10/2 + 1)^"th" "term"}`
= `1/2{5^"th" "term" + 6^"th" "term"}`
= `1/2{36 + 39}`
= `1/2(75)`
= 37.5
∴ Median = 37.5
If 35 is added to the above data then it will be the 5th term then number of data n = 11, which is odd
∴ Median = `(("n" + 1)/2)^"th"` term
= `((11 + 1)/2)^"th"` term
= `(12/2)^"th"` term
= 6th term
New median = 36
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संबंधित प्रश्न
The distribution given below shows the marks obtained by 25 students in an aptitude test. Find the mean, median and mode of the distribution.
Marks obtained | 5 | 6 | 7 | 8 | 9 | 10 |
No. of students | 3 | 9 | 6 | 4 | 2 | 1 |
Using the information given in the adjoining histogram, calculate the mean.
Find the mode of following data, using a histogram:
Class | 0 – 10 | 10 – 20 | 20 – 30 | 30 – 40 | 40 – 50 |
Frequency | 5 | 12 | 20 | 9 | 4 |
Find the mean of the following frequency distribution by the step deviation method :
Class | 0-20 | 20-40 | 40-60 | 60-80 | 80-100 | 100-120 | 120-140 |
Frequency | 12 | 24 | 52 | 88 | 66 | 42 | 16 |
The marks of 200 students in a test is given below :
Marks% | 10-19 | 20-29 | 30-39 | 40-49 | 50-59 | 60-69 | 70-79 | 80-89 |
No. of Students | 7 | 11 | 20 | 46 | 57 | 37 | 15 | 7 |
Draw an ogive and find
(i) the median
(ii) the number of students who scored more than 35% marks
Estimate the median, the lower quartile and the upper quartile of the following frequency distribution by drawing an ogive:
Marks | 30-40 | 40-50 | 50-60 | 60-70 | 70-80 | 80-90 | 90-100 |
No. of boys | 10 | 12 | 14 | 12 | 9 | 7 | 6 |
Find the mean of all factors of 10.
Find the mean of: 5, 2.4, 6.2, 8.9, 4.1 and 3.4
Find the median of 1,3,4, 5, 9, 9 and 11
Find the mean and the median of: 5, 8, 10, 11,13, 16, 19 and 20