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प्रश्न
Find the mean and the median of: 5, 8, 10, 11,13, 16, 19 and 20
उत्तर
Given data: 5, 8, 10, 11,13, 16, 19 and 20
Here, number of data = 8 which is even
∴ Median =`1/2 {"n"/2 "th term" + ("n"/2 + 1)"th term"}`
`= 1/2 {8/2 "th term" + (8/2 + 1) "th term"}`
`= 1/2 {4 "th term" + 5 "th term"}`
`= 1/2 {11 + 13}`
`= 1/2 xx 24 = 12`
∴ Median = 12
Mean = `"Sum of observations"/"Number of observations"`
`= (5 + 8 + 10 + 11 + 13 + 16 + 19 + 20)/8`
`= 102/8 = 17.75`
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संबंधित प्रश्न
Calculate the mean of the following distribution using step deviation method.
Marks | 0-10 | 10-20 | 20-30 | 30-40 | 40-50 | 50-60 |
Number of students |
10 | 9 | 25 | 0 | 16 | 10 |
The following distribution represents the height of 160 students of a school.
Height (in cm) | No. of Students |
140 – 145 | 12 |
145 – 150 | 20 |
150 – 155 | 30 |
155 – 160 | 38 |
160 – 165 | 24 |
165 – 170 | 16 |
170 – 175 | 12 |
175 – 180 | 8 |
Draw an ogive for the given distribution taking 2 cm = 5 cm of height on one axis and 2 cm = 20 students on the other axis. Using the graph, determine:
- The median height.
- The interquartile range.
- The number of students whose height is above 172 cm.
The following table gives the weekly wages of workers in a factory.
Weekly wages (Rs) | No. of workers |
50 – 55 | 5 |
55 – 60 | 20 |
60 – 65 | 10 |
65 – 70 | 10 |
70 – 75 | 9 |
75 – 80 | 6 |
80 – 85 | 12 |
85 – 90 | 8 |
Calculate the mean by using:
Direct Method
The following table gives the weekly wages of workers in a factory.
Weekly wages (Rs) | No. of workers |
50 – 55 | 5 |
55 – 60 | 20 |
60 – 65 | 10 |
65 – 70 | 10 |
70 – 75 | 9 |
75 – 80 | 6 |
80 – 85 | 12 |
85 – 90 | 8 |
Calculate the mean by using:
Short-cut method
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