Advertisements
Advertisements
Question
Find the mean and the median of: 5, 8, 10, 11,13, 16, 19 and 20
Solution
Given data: 5, 8, 10, 11,13, 16, 19 and 20
Here, number of data = 8 which is even
∴ Median =`1/2 {"n"/2 "th term" + ("n"/2 + 1)"th term"}`
`= 1/2 {8/2 "th term" + (8/2 + 1) "th term"}`
`= 1/2 {4 "th term" + 5 "th term"}`
`= 1/2 {11 + 13}`
`= 1/2 xx 24 = 12`
∴ Median = 12
Mean = `"Sum of observations"/"Number of observations"`
`= (5 + 8 + 10 + 11 + 13 + 16 + 19 + 20)/8`
`= 102/8 = 17.75`
APPEARS IN
RELATED QUESTIONS
Find mean by step-deviation method:
C.I. | 63 – 70 | 70 – 77 | 77 – 84 | 84 – 91 | 91 – 98 | 98 – 105 | 105 – 112 |
Frequency | 9 | 13 | 27 | 38 | 32 | 16 | 15 |
A boy scored following marks in various class tests during a term; each test being marked out of 20.
15, 17, 16, 7, 10, 12, 14, 16, 19, 12 and 16
What are his mean marks?
The marks of 20 students in a test were as follows:
2, 6, 8, 9, 10, 11, 11, 12, 13, 13, 14, 14, 15, 15, 15, 16, 16, 18, 19 and 20.
Calculate:
- the mean
- the median
- the mode
find the mean for the following frequency distribution:
C.I | 0-50 | 50-100 | 100-150 | 150-200 | 200-250 | 250-300 |
Freq | 4 | 8 | 16 | 13 | 6 | 3 |
Find the arithmetic mean (correct to the nearest whole number) by using step-deviation method.
x | 5 | 10 | 15 | 20 | 25 | 30 | 35 | 40 | 45 | 50 |
f | 20 | 43 | 75 | 67 | 72 | 45 | 39 | 9 | 8 | 6 |
The weights of 11 students in a class are 36 kg, 45 kg, 44 kg, 37 kg, 36 kg, 41 kg, 45 kg, 43 kg, 39 kg, 42 kg and 40 kg. Find the median of their weights.
The marks of 200 students in a test is given below :
Marks% | 10-19 | 20-29 | 30-39 | 40-49 | 50-59 | 60-69 | 70-79 | 80-89 |
No. of Students | 7 | 11 | 20 | 46 | 57 | 37 | 15 | 7 |
Draw an ogive and find the number of students who scored more than 35% marks
Find the median of:
233, 173, 189, 208, 194, 204, 194, 185, 200 and 220.
The following observations have been arranged in ascending order. If the median of these observations is 58, find the value of x.
24, 27, 43, 48, x - 1, x + 3, 68, 73, 80, 90
The median first 6 odd natural numbers is ____________