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प्रश्न
Find the mean and the median of: 2, 4, 5, 8, 10,13 and 14
उत्तर
Given data = 2, 4, 5, 8, 10, 13 and 14
Clearly, middle term is 8
∴ Median = 8
∴ Mean = `"sum of observations"/"Number of observations"`
`= (2 + 4 + 5 +8 + 10 + 13 + 14)/7 = 56/7 = 8`
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संबंधित प्रश्न
Calculate the mean of the following distribution :
| Class Interval | 0-10 | 10-20 | 20-30 | 30-40 | 40-50 | 50-60 |
| Frequency | 8 | 5 | 12 | 35 | 24 | 16 |
Find the mean of the natural numbers from 3 to 12.
The marks of 200 students in a test were recorded as follows:
| Marks | No. of students |
| 10-19 | 7 |
| 20-29 | 11 |
| 30-39 | 20 |
| 40-49 | 46 |
| 50-59 | 57 |
| 60-69 | 37 |
| 70-79 | 15 |
| 80-89 | 7 |
Construct the cumulative frequency table. Drew the ogive and use it too find:
(1) the median and
(2) the number of student who score more than 35% marks.
What is the median of 7, 10, 7, 5, 9, 10?
The mean of the following frequency distribution is 25.8 and the sum of all the frequencies is 50. Find x and y.
| Class | 0-10 | 10-20 | 20-30 | 30-40 | 40-50 |
| Frequency | 7 | x | 15 | y | 10 |
The frequency distribution table below shows the height of 50 students of grade 10.
| Heights (in cm) | 138 | 139 | 140 | 141 | 142 |
| Frequency | 6 | 11 | 16 | 10 | 7 |
Find the median, the upper quartile and the lower quartile of the heights.
Mean of 5 numbers is 20 and the mean of the other 5 numbers is 30. Find the mean of all the 10 numbers taken together.
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