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प्रश्न
Find the median of the given data: 36, 44, 86, 31, 37, 44, 86, 35, 60, 51
उत्तर
Arrange the values in ascending order we get
31, 35, 36, 37, 44, 44, 51, 60, 86, 86
The number of values = 10 which is even
Median = Average of `(10/2)^"th"` and `(10/2 + 1)^"th"` value
= Average of 5th and 6th value
= `(44 + 44)/2`
= `88/2`
= 44
∴ Median = 44
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संबंधित प्रश्न
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| Frequency | 2 | 5 | 18 | 14 | 8 | 5 |
Find the mode of the following data:
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For the following set of data, find the median:
10, 75, 3, 81, 17, 27, 4, 48, 12, 47, 9 and 15.
Using a graph paper, draw an ogive for the following distribution which shows a record of the width in kilograms of 200 students.
| Weight | Frequency |
| 40 – 45 | 5 |
| 45 – 50 | 17 |
| 50 – 55 | 22 |
| 55 – 60 | 45 |
| 60 – 65 | 51 |
| 65 – 70 | 31 |
| 70 – 75 | 20 |
| 75 – 80 | 9 |
Use your ogive to estimate the following:
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- overweight, If 55.70 kg is considered as standard weight.
Calculate the mean of the distribution, given below using the short cut method:
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| No. of students | 2 | 6 | 10 | 12 | 9 | 7 | 4 |
Find the mean of the following frequency distribution :
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| Frequency | 4 | 7 | 6 | 3 | 5 |
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21, 22, 28, 23, 24, 21 26, 22, 29, 27, 21, 21, 26, 24, 23
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3, 4, 5, 7, 6, 3, 5, 4, 3, 5, 6, 4, 7, 5, 4, 5, 4, 3, 4, 5, 7, 6, 5, 6, 6, 7
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