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प्रश्न
The median of observation 11, 12, 14, 18, x + 2, x + 4, 30, 32, 35, 41 arranged in ascending order is 24. Find the values of x
उत्तर
The given observation is 11, 12, 14, 18, x + 2, x + 4, 30, 32, 35, 41 ...(is ascending order)
The number of values = 10
Median = Average of `(10/2)^"th"` and `(10/2 + 1)^"th"` value
= Average of 5th and 6th value
24 = `(x + 2 + x + 4)/2`
24 = `(2x + 6)/2`
2x + 6 = 48
2x = 48 – 6
2x = 42
x = `42/2`
= 21
The value of x = 21
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संबंधित प्रश्न
The marks of 20 students in a test were as follows:
2, 6, 8, 9, 10, 11, 11, 12, 13, 13, 14, 14, 15, 15, 15, 16, 16, 18, 19 and 20.
Calculate:
- the mean
- the median
- the mode
Find the mean (correct to one place of decimal) by using short-cut method.
x |
40 |
41 |
43 |
45 |
46 |
49 |
50 |
f |
14 |
28 |
38 |
50 |
40 |
20 |
10 |
In a case of 40 students, marks obtained by the students in a class test (out of 10) are given below:
Marks | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 | 10 |
Number of students | 1 | 2 | 3 | 3 | 6 | 10 | 5 | 4 | 3 | 3 |
Calculate the following for the given distribution:
(i) Median
(ii) Mode
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Find the mean of the following frequency distribution :
Class | 0-10 | 10-20 | 20-30 | 30-40 | 40-50 | 50-60 | 60-70 |
Frequency | 4 | 4 | 7 | 10 | 12 | 8 | 5 |
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No. of people | 9 | 17 | 23 | 15 | 6 | 5 |
Estimate the median, the lower quartile and the upper quartile of the following frequency distribution by drawing an ogive:
Marks (less than) | 10 | 20 | 30 | 40 | 50 | 60 | 70 | 80 |
No. of students | 5 | 15 | 30 | 54 | 72 | 86 | 94 | 100 |
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