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प्रश्न
Find the median of the following frequency distribution :
| Salarv fin Rs) | 3500 | 4000 | 4500 | 5000 | 5500 | 6000 |
| No. of people | 9 | 17 | 23 | 15 | 6 | 5 |
उत्तर
| Salary (in Rs) | No. of students (f) | Cumulative frequency |
| 3500 | 9 | 9 |
| 4000 | 17 | 26 |
| 4500 | 23 | 49 |
| 5000 | 15 | 64 |
| 5500 | 6 | 70 |
| 6000 | 5 | 75 |
No. of terms = 75
median = `(75 + 1)/2` = 38th term
38th term lies under 4500
Hence, Median = 4500
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संबंधित प्रश्न
Draw a histogram from the following frequency distribution and find the mode from the graph:
| Class | 0-5 | 5-10 | 10-15 | 15-20 | 20-25 | 25-30 |
| Frequency | 2 | 5 | 18 | 14 | 8 | 5 |
Marks obtained (in mathematics) by 9 students are given below:
60, 67, 52, 76, 50, 51, 74, 45 and 56
- Find the arithmetic mean.
- If marks of each student be increased by 4; what will be the new value of arithmetic mean?
Using a graph paper, draw an ogive for the following distribution which shows a record of the width in kilograms of 200 students.
| Weight | Frequency |
| 40 – 45 | 5 |
| 45 – 50 | 17 |
| 50 – 55 | 22 |
| 55 – 60 | 45 |
| 60 – 65 | 51 |
| 65 – 70 | 31 |
| 70 – 75 | 20 |
| 75 – 80 | 9 |
Use your ogive to estimate the following:
- The percentage of student weighting 55 kg or more
- The weight above which the heaviest 30% of the student fall
- The number of students who are
- underweight
- overweight, If 55.70 kg is considered as standard weight.
In a case of 40 students, marks obtained by the students in a class test (out of 10) are given below:
| Marks | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 | 10 |
| Number of students | 1 | 2 | 3 | 3 | 6 | 10 | 5 | 4 | 3 | 3 |
Calculate the following for the given distribution:
(i) Median
(ii) Mode
The data on the number of patients attending a hospital in a month are given below. Find the average (mean) number of patients attending the hospital in a month by using the shortcut method. Take the assumed mean as 45. Give your answer correct to 2 decimal places.
| Number of patients | 10 - 20 | 20 - 30 | 30 - 40 | 40 - 50 | 50 - 60 | 60 - 70 |
| Number of Days | 5 | 2 | 7 | 9 | 2 | 5 |
What is the median of 7, 10, 7, 5, 9, 10?
Find the mean of the following frequency distribution :
| Class | 25-35 | 35-45 | 45-55 | 55-65 | 65-75 |
| Frequency | 6 | 10 | 8 | 12 | 4 |
Find the mean of: 7, 5, 0, 3, 0, 6, 0, 9, 1 and 4
The marks in a subject for 12 students are as follows:
31, 37, 35, 38, 42, 23, 17, 18, 35, 25, 35, 29
For the given data, find the median
An incomplete frequency distribution is given below
| Variate | Frequency |
| 10 – 20 | 12 |
| 20 – 30 | 30 |
| 30 – 40 | ? |
| 40 – 50 | 65 |
| 50 – 60 | 45 |
| 60 – 70 | 25 |
| 70 – 80 | 18 |
| Total | 229 |
Median value is 46, the missing frequency is:
