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प्रश्न
Find the median of the following frequency distribution :
| Weight(kg) | 36 | 38 | 40 | 42 | 44 |
| No. of students | 11 | 26 | 29 | 24 | 10 |
उत्तर
| Weight (kg) | No. of students (f) |
Cumulative frequency |
| 36 | 11 | 11 |
| 38 | 26 | 37 |
| 40 | 29 | 66 |
| 42 | 24 | 90 |
| 44 | 10 | 100 |
No. of terms = 100
The mean of 50th and 51st term is the median
50th and 51st terms lay under 40 and 40
median = `(40+40 )/2 = 40`
Hence, Median = 40
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संबंधित प्रश्न
Find the mode and the median of the following frequency distribution:
| x | 10 | 11 | 12 | 13 | 14 | 15 |
| f | 1 | 4 | 7 | 5 | 9 | 3 |
The following are the marks obtained by 70 boys in a class test:
| Marks | No. of boys |
| 30 – 40 | 10 |
| 40 – 50 | 12 |
| 50 – 60 | 14 |
| 60 – 70 | 12 |
| 70 – 80 | 9 |
| 80 – 90 | 7 |
| 90 – 100 | 6 |
Calculate the mean by:
Step-deviation method
Draw an ogive for the data given below and from the graph determine:
- the median marks
- the number of students who obtained more than 75% marks
| Marks | No. of students |
| 0 – 9 | 5 |
| 10 – 19 | 9 |
| 20 – 29 | 16 |
| 30 – 39 | 22 |
| 40 – 49 | 26 |
| 50 – 59 | 18 |
| 60 – 69 | 11 |
| 70 – 79 | 6 |
| 80 – 89 | 4 |
| 90 – 99 | 3 |
Find the mean of the following frequency distribution by the short cut method :
| Class | 1-10 | 11-20 | 21-30 | 31-40 | 41-50 | 51-60 | 61-70 |
| Frequency | 7 | 10 | 14 | 17 | 15 | 11 | 6 |
The following observations have been arranged in ascending order. If the median of these observations is 58, find the value of x.
24, 27, 43, 48, x - 1, x + 3, 68, 73, 80, 90
Find the mean of first six natural numbers.
The mean of a certain number of observations is 32. Find the resulting mean, if the observation is, divided by 0.5
Find the mean of: first six even natural numbers
Find the median of the following sets of numbers.
25, 11, 15, 10, 17, 6, 5, 12.
An incomplete frequency distribution is given below
| Variate | Frequency |
| 10 – 20 | 12 |
| 20 – 30 | 30 |
| 30 – 40 | ? |
| 40 – 50 | 65 |
| 50 – 60 | 45 |
| 60 – 70 | 25 |
| 70 – 80 | 18 |
| Total | 229 |
Median value is 46, the missing frequency is:
