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Question
Find the median of the following frequency distribution :
| Weight(kg) | 36 | 38 | 40 | 42 | 44 |
| No. of students | 11 | 26 | 29 | 24 | 10 |
Solution
| Weight (kg) | No. of students (f) |
Cumulative frequency |
| 36 | 11 | 11 |
| 38 | 26 | 37 |
| 40 | 29 | 66 |
| 42 | 24 | 90 |
| 44 | 10 | 100 |
No. of terms = 100
The mean of 50th and 51st term is the median
50th and 51st terms lay under 40 and 40
median = `(40+40 )/2 = 40`
Hence, Median = 40
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