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प्रश्न
In a case of 40 students, marks obtained by the students in a class test (out of 10) are given below:
Marks | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 | 10 |
Number of students | 1 | 2 | 3 | 3 | 6 | 10 | 5 | 4 | 3 | 3 |
Calculate the following for the given distribution:
(i) Median
(ii) Mode
उत्तर
Marks (x) |
No.of Students | c.f |
1 | 1 | 1 |
2 | 2 | 3 |
3 | 3 | 6 |
4 | 3 | 9 |
5 | 6 | 15 |
6 | 10 | 25 |
7 | 5 | 30 |
8 | 4 | 34 |
9 | 3 | 37 |
10 | 3 | 40 |
Total | 40 |
(i) Total number of Students = 40 which is even
Median =`1/2[(n/2)+(n/2+1)^(th) "term"]`
= `1/2[(40/2)+(40/2+1)"term"]`
=`1/2[20^(th) " term" + 21^(th)" term"]`
=`(41/2)^(th) ` term
= 20.5th term
Which is between 15 and 25.
∴ Median = 6
(ii) Mode frequency of 6 is the highest.
∴ Mode = 3
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संबंधित प्रश्न
Using a graph paper draw a histogram of the given distribution showing the number of runs scored by 50 batsmen. Estimate the mode of the data:
Runs scored |
3000- 4000 |
4000- 5000 |
5000- 6000 |
6000- 7000 |
7000- 8000 |
8000- 9000 |
9000- 10000 |
No. of batsmen |
4 | 18 | 9 | 6 | 7 | 2 | 4 |
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2) State the modal class.
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Frequency | 5 | 20 | 10 | 10 | 9 | 6 | 12 | 8 |
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From the following cumulative frequency table, draw ogive and then use it to find:
- Median
- Lower quartile
- Upper quartile
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Cumulative frequency | 5 | 24 | 37 | 40 | 42 | 48 | 70 | 77 | 79 | 80 |
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