Advertisements
Advertisements
प्रश्न
Using the factor theorem, show that (x - 2) is a factor of `x^3 + x^2 -4x -4 .`
Hence factorise the polynomial completely.
उत्तर
`f(x) = x^3 + x^2 - 4x - 4`
Let x - 2 = 0, then x = 2
`therefore f(2) = (2)^3 +(2)^2 - 4 (2)-4`
f (2) = 8 + 4 - 8 - 4
f (2) = 0
∴ x - 2 is a factor of f (x)
Now dividing x3 + x2 - 4x - 4 by x - 2, we get
`=x^3 +x^2 - 4x +4 = (x-2)(x^2 + 3x + 2)`
= (x - 2) (x + 2) (x + 1 )
APPEARS IN
संबंधित प्रश्न
When divided by x – 3 the polynomials x3 – px2 + x + 6 and 2x3 – x2 – (p + 3) x – 6 leave the same remainder. Find the value of ‘p’.
Given that x – 2 and x + 1 are factors of f(x) = x3 + 3x2 + ax + b; calculate the values of a and b. Hence, find all the factors of f(x).
Show that (x – 1) is a factor of x3 – 7x2 + 14x – 8. Hence, completely factorise the given expression.
If (x + 1) and (x – 2) are factors of x3 + (a + 1)x2 – (b – 2)x – 6, find the values of a and b. And then, factorise the given expression completely.
Using remainder Theorem, factorise:
2x3 + 7x2 − 8x – 28 Completely
In the following two polynomials, find the value of ‘a’ if x – a is a factor of each of the two:
x6 - ax5 + x4 - ax3 + 3a + 2
If x – 2 is a factor of each of the following three polynomials. Find the value of ‘a’ in each case:
x3 + 2ax2 + ax - 1
If x – 2 is a factor of each of the following three polynomials. Find the value of ‘a’ in each case:
x5 - 3x4 - ax3 + 3ax2 + 2ax + 4.
If (x – 2) is a factor of 2x3 – x2 + px – 2, then
(i) find the value of p.
(ii) with this value of p, factorise the above expression completely
If f(x) = 3x + 8; the value of f(x) + f(– x) is ______.